博客
关于我
剑指offer--树--树中两个结点的最低公共祖先
阅读量:135 次
发布时间:2019-02-26

本文共 2510 字,大约阅读时间需要 8 分钟。

???????????????????????????????

  • ??????????????????????????????????????DFS???????
  • ??????????????????????????????????????????????
  • ??????????????

    import java.util.ArrayList;import java.util.Stack;public class Test2 {    public static void main(String[] args) {        // ????        TreeNode root = new TreeNode(6);        TreeNode left = new TreeNode(2);        left.left = new TreeNode(0);        left.right = new TreeNode(4);        left.right.left = new TreeNode(7);        left.right.right = new TreeNode(9);        root.left = left;        TreeNode right = new TreeNode(8);        right.left = new TreeNode(3);        right.left.right = new TreeNode(5);        root.right = right;        System.out.println(lowestCommonAncestorII(root, left, right));    }    public static TreeNode lowestCommonAncestorII(TreeNode root, TreeNode p, TreeNode q) {        List
    pPath = findPath(root, p); List
    qPath = findPath(root, q); // ??????????null if (pPath == null || qPath == null) { return null; } // ??????????????? int minLength = Math.min(pPath.size(), qPath.size()); TreeNode common = null; for (int i = 0; i < minLength; i++) { if (pPath.get(i) == qPath.get(i)) { common = pPath.get(i); } else { break; } } return common; } private static List
    findPath(TreeNode root, TreeNode target) { List
    path = new ArrayList<>(); Stack
    stack = new Stack<>(); stack.push(root); while (!stack.isEmpty()) { TreeNode node = stack.pop(); if (node == target) { // ????????????path? while (!stack.isEmpty()) { path.add(stack.pop()); } return path; } if (node.left != null) { stack.push(node.left); } if (node.right != null) { stack.push(node.right); } } return null; }}

    ????

  • findPath ???

    • ?????????????DFS?????????????????
    • ???????????????????????????????????
  • lowestCommonAncestorII ???

    • ?? findPath ??????????p?q????
    • ?????????????????????
    • ?????????????????????????????????????
  • ??????

    • main ???????????? lowestCommonAncestorII ???????????
    • lowestCommonAncestorII ?????????????????????????????
    • findPath ????????DFS?????????

    ????????????O(n)???????????????????????????????

    转载地址:http://tnzu.baihongyu.com/

    你可能感兴趣的文章
    qt批量操作同类型控件
    查看>>
    Portaudio笔记-WASAPI
    查看>>
    position:fixed失效情况
    查看>>
    Qt开发笔记:QGLWidget、QOpenGLWidget详解及区别
    查看>>
    Position属性四个值:static、fixed、absolute和relative的区别和用法
    查看>>
    POSIX thread编程中关于临界区内条件变量的分析
    查看>>
    POSIX与程序可移植性
    查看>>
    posix多线程有感--自旋锁
    查看>>
    SpringBoot中集成海康威视SDK实现布防报警数据上传/交通违章图片上传并在linux上部署(附示例代码资源)
    查看>>
    POSIX标准和XSI扩展
    查看>>
    post install error,please remove node_moules before retry
    查看>>
    postcss-pxtorem 参数之selectorBlackList、exclude的用法
    查看>>
    Postek博思得标签打印机更换电脑,打印出来标签空白
    查看>>
    postfix+ dovecot搭建邮件服务器
    查看>>
    postfix在邮件服务器中的使用
    查看>>
    PostGIS 3.1.2软件安装详细教程(地图工具篇.8)
    查看>>
    PostGIS中获取所有EPSG的编码以及对应Proj4字符串
    查看>>
    SpringBoot中集成海康威视SDK实现布防报警数据上传/交通违章图片上传并在linux上部署(附示例代码资源)
    查看>>
    PostGIS在Windows上的下载与安装
    查看>>
    Qt开发——网络编程之UDP客户端
    查看>>